(x^4-16)/(x^2-4x-12)=0

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Solution for (x^4-16)/(x^2-4x-12)=0 equation: 


D( x )

x^2-(4*x)-12 = 0

x^2-(4*x)-12 = 0

x^2-(4*x)-12 = 0

x^2-4*x-12 = 0

x^2-4*x-12 = 0

DELTA = (-4)^2-(-12*1*4)

DELTA = 64

DELTA > 0

x = (64^(1/2)+4)/(1*2) or x = (4-64^(1/2))/(1*2)

x = 6 or x = -2

x in (-oo:-2) U (-2:6) U (6:+oo)

(x^4-16)/(x^2-(4*x)-12) = 0

(x^4-16)/(x^2-4*x-12) = 0

x^2-4*x-12 = 0

x^2-4*x-12 = 0

DELTA = (-4)^2-(-12*1*4)

DELTA = 64

DELTA > 0

x = (64^(1/2)+4)/(1*2) or x = (4-64^(1/2))/(1*2)

x = 6 or x = -2

(x+2)*(x-6) = 0

(x^4-16)/((x+2)*(x-6)) = 0

1*x^4 = 16 // : 1

x^4 = 16

x^4 = 16 // ^ 1/4

abs(x) = 2

x = 2 or x = -2

x in { -2} 

x = 2

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